Factorise:
(x2 - 2xy + y2) - z2
We have   (x2 - 2xy + y2) = (x - y)2
∴ (x2 - 2xy + y2) - z2 = (x - y)2 - (z)2     Â
                                        = [(x - y) + z] [(x - y) - z]
                                               [Using a2 - b2 = (a + b) (a - b)]
                              = (x - y + z)(x - y - z)
∴ (x2 - 2xy + y2) - z2 = (x - y + z) (x - y -z)