Factorise the expression and divide them as directed.
39y3(50y2 - 98) 26y2(5y + 7)
∵            50y2 - 98 = 2(25y2 - 49)
                           = 2[(5y)2 - (7)2]
                           =2[(5y - 7)(5y + 7)]
∴    Â
                                  =
Thus, 39y3(50y2 - 98) / 26y2(5y + 7) = 3y(5y - 7)