Evaluate the following definite integral from Mathematics Inte

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 Multiple Choice QuestionsShort Answer Type

41.

Evaluate the following definite integral
integral subscript 0 superscript straight pi over 4 end superscript space sin space 2 straight x space dx









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42.

Evaluate the following definite integral
integral subscript straight pi over 6 end subscript superscript straight pi over 4 end superscript space cosec space straight x space dx

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43.

Evaluate the following definite integral
integral subscript 4 superscript 5 straight e to the power of straight x dx

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44.

Evaluate the following definite integral
integral subscript 0 superscript straight pi over 4 end superscript space left parenthesis 2 sec squared straight x plus straight x cubed plus 2 right parenthesis dx


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45.

Evaluate the following definite integral
integral subscript 0 superscript straight pi over 4 end superscript left parenthesis 2 sec squared straight x plus straight x cubed plus 2 right parenthesis space dx

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46.

Evaluate the following definite integral
integral subscript 0 superscript straight pi open parentheses sin squared straight x over 2 minus cos squared straight x over 2 close parentheses space dx

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47.

Evaluate the following definite integral
integral subscript 1 superscript 2 left parenthesis 4 straight x cubed minus 5 straight x squared plus 6 straight x plus 9 right parenthesis space dx.



Let I = integral subscript 1 superscript 2 left parenthesis 4 straight x cubed minus 5 straight x squared plus 6 straight x plus 9 right parenthesis space dx
        equals space open square brackets fraction numerator 4 straight x to the power of 4 over denominator 4 end fraction minus fraction numerator 5 straight x cubed over denominator 3 end fraction plus fraction numerator 6 straight x squared over denominator 2 end fraction plus 9 straight x close square brackets subscript 1 superscript 2 space equals space open square brackets straight x to the power of 4 minus 5 over 3 straight x cubed plus 3 straight x squared plus 9 straight x close square brackets subscript 1 superscript 2
equals space open parentheses 16 minus 40 over 3 plus 12 plus 18 close parentheses space minus space open parentheses 1 minus 5 over 3 plus 3 plus 9 close parentheses space equals space 32 2 over 3 minus 11 1 third space equals space 21 1 third

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48.

Evaluate integral subscript 0 superscript 1 fraction numerator dx over denominator square root of 1 plus straight x end root minus square root of straight x end fraction.

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49.

Evaluate integral subscript 0 superscript 1 space straight x space straight e to the power of straight x squared space dx

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50. Evaluate the following integral:
integral subscript 0 superscript 1 fraction numerator 1 over denominator square root of 1 minus straight x squared end root end fraction dx
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