Explain the following integral: from Mathematics Integrals

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 Multiple Choice QuestionsShort Answer Type

51.

Explain the following integral:
space integral subscript 0 superscript 1 fraction numerator 1 over denominator 1 plus straight x squared end fraction dx

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52.

Explain the following integral:
integral subscript 2 superscript 3 fraction numerator 1 over denominator straight x squared minus 1 end fraction dx

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53.

Explain the following integral:
integral subscript 2 superscript 3 fraction numerator straight x over denominator straight x squared plus 1 end fraction dx


Let I = integral subscript 2 superscript 3 fraction numerator straight x over denominator straight x squared plus 1 end fraction dx space equals space 1 half integral subscript 2 superscript 3 fraction numerator 2 straight x over denominator straight x squared plus 1 end fraction dx space equals space 1 half left square bracket log left parenthesis straight x squared plus 1 right parenthesis right square bracket subscript 2 superscript 3 space space space
        equals space 1 half left parenthesis log space 10 space minus space log space 5 right parenthesis space equals space 1 half log open parentheses 10 over 5 close parentheses space equals space 1 half log 2

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54. Evaluate the following integral:
integral subscript 1 superscript 2 fraction numerator dx over denominator left parenthesis straight x plus 1 right parenthesis space left parenthesis straight x plus 2 right parenthesis end fraction
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55. Evaluate the following integral:
integral subscript 1 superscript 2 fraction numerator 5 straight x squared over denominator straight x squared plus 4 straight x plus 3 end fraction dx

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56. Evaluate the following integral
space integral subscript 2 superscript 3 fraction numerator 1 over denominator straight x squared minus 1 end fraction dx



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57. Evaluate the following integral:
space space integral subscript 0 superscript 4 fraction numerator dx over denominator square root of straight x squared plus 2 straight x plus 3 end root end fraction
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58. Evaluate the following integral:
integral subscript 4 superscript 9 fraction numerator square root of straight x over denominator open parentheses 30 minus straight x to the power of begin display style 3 over 2 end style end exponent close parentheses squared end fraction dx

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59.

Evaluate the following definite integral
integral subscript 0 superscript 2 fraction numerator 6 straight x plus 3 over denominator straight x squared plus 4 end fraction dx.

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60.

Evaluate the following definite integral
integral subscript 0 superscript 1 fraction numerator 2 straight x over denominator 5 straight x squared plus 1 end fraction dx

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