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Prove the following:
$integral subscript 1 superscript 3 fraction numerator dx over denominator straight x squared left parenthesis straight x plus 1 right parenthesis end fraction space equals space 2 over 3 plus log 2 over 3$

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Short Answer Type

82.

Prove the following:
$integral subscript 0 superscript straight pi over 4 end superscript space 2 space tan cubed straight x space dx space equals space 1 minus log space 2.$

113 Views

83.

Prove the following:
$integral subscript 0 superscript 1 square root of fraction numerator 1 minus straight x over denominator 1 plus straight x end fraction dx end root space equals space straight pi over 2 minus 1.$

90 Views

Multiple Choice Questions

84.

integral subscript 1 superscript square root of 3 end superscript fraction numerator dx over denominator 1 plus straight x squared end fraction

equals

$straight pi over 3$
$fraction numerator 2 straight pi over denominator 3 end fraction$
$straight pi over 6$
$straight pi over 6$

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85. $integral subscript 0 superscript 2 over 3 end superscript fraction numerator dx over denominator 4 plus 9 straight x squared end fraction space equals$
$straight pi over 6$
$straight pi over 12$
$straight pi over 24$
$straight pi over 24$

straight pi over 24

Let
I = $integral subscript 0 superscript 2 over 3 end superscript fraction numerator dx over denominator 4 plus 9 straight x squared end fraction space equals space 1 over 9 integral subscript 0 superscript 2 over 3 end superscript fraction numerator 1 over denominator begin display style 4 over 9 end style plus straight x squared end fraction dx space equals space 1 over 9 integral subscript 0 superscript 2 over 3 end superscript fraction numerator 1 over denominator open parentheses begin display style 2 over 3 end style close parentheses squared plus straight x squared end fraction dx$
$equals space 1 over 9. fraction numerator 1 over denominator begin display style 2 over 3 end style end fraction open square brackets tan to the power of negative 1 end exponent open parentheses fraction numerator straight x over denominator begin display style 2 over 3 end style end fraction close parentheses close square brackets subscript 0 superscript 2 over 3 end superscript space equals space 1 over 6 open square brackets tan to the power of negative 1 end exponent open parentheses fraction numerator 3 straight x over denominator 2 end fraction close parentheses close square brackets subscript 0 superscript 2 over 3 end superscript equals space 1 over 6 left parenthesis tan to the power of negative 1 end exponent space 1 space minus space tan to the power of negative 1 end exponent 0 right parenthesis space equals space 1 over 6 open parentheses straight pi over 4 minus 0 close parentheses space equals space straight pi over 24$

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Short Answer Type

86.

Evaluate $integral subscript 0 superscript 2 straight pi end superscript fraction numerator cosx over denominator square root of 4 plus 3 sinx end root end fraction dx.$

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87.

Evaluate $integral subscript 0 superscript straight pi over 6 end superscript left parenthesis 1 minus cos space 3 straight theta right parenthesis space sin space 3 straight theta space dθ$

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88.

Evaluate $integral subscript 0 superscript straight pi space 5 space left parenthesis 5 minus 4 space cosθ right parenthesis to the power of 1 fourth end exponent space sin space straight theta space dθ$

94 Views

89.

Evaluate $integral subscript 0 superscript straight pi over 6 end superscript space cos to the power of negative 3 end exponent 2 straight theta space sin space 2 straight theta space dθ$

152 Views

90.

Evaluate $space integral subscript 0 superscript 3 square root of straight pi squared end root end superscript square root of straight x space cos squared open parentheses straight x to the power of 3 over 2 end exponent close parentheses dx.$