Evaluate  from Mathematics Integrals

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsLong Answer Type

81.

Prove the following:
integral subscript 1 superscript 3 fraction numerator dx over denominator straight x squared left parenthesis straight x plus 1 right parenthesis end fraction space equals space 2 over 3 plus log 2 over 3


99 Views

 Multiple Choice QuestionsShort Answer Type

82.

Prove the following:
integral subscript 0 superscript straight pi over 4 end superscript space 2 space tan cubed straight x space dx space equals space 1 minus log space 2.



113 Views

83.

Prove the following:
integral subscript 0 superscript 1 square root of fraction numerator 1 minus straight x over denominator 1 plus straight x end fraction dx end root space equals space straight pi over 2 minus 1.




90 Views

 Multiple Choice QuestionsMultiple Choice Questions

84. integral subscript 1 superscript square root of 3 end superscript fraction numerator dx over denominator 1 plus straight x squared end fraction equals

  • straight pi over 3
  • fraction numerator 2 straight pi over denominator 3 end fraction
  • straight pi over 6
  • straight pi over 6
113 Views

Advertisement
85. integral subscript 0 superscript 2 over 3 end superscript fraction numerator dx over denominator 4 plus 9 straight x squared end fraction space equals
  • straight pi over 6
  • straight pi over 12
  • straight pi over 24
  • straight pi over 24
97 Views

 Multiple Choice QuestionsShort Answer Type

86.

Evaluate integral subscript 0 superscript 2 straight pi end superscript fraction numerator cosx over denominator square root of 4 plus 3 sinx end root end fraction dx.

130 Views

87.

Evaluate integral subscript 0 superscript straight pi over 6 end superscript left parenthesis 1 minus cos space 3 straight theta right parenthesis space sin space 3 straight theta space dθ

97 Views

Advertisement

88.

Evaluate integral subscript 0 superscript straight pi space 5 space left parenthesis 5 minus 4 space cosθ right parenthesis to the power of 1 fourth end exponent space sin space straight theta space dθ


Let I = integral subscript 0 superscript straight pi 5 space left parenthesis 5 minus 4 cosθ right parenthesis to the power of 1 fourth end exponent space sin space straight theta space dθ space equals space 5 integral subscript 0 superscript straight pi left parenthesis 5 minus 4 space cosθ right parenthesis to the power of 1 fourth end exponent space sin space straight theta space dθ
Put 5 minus 4 space cosθ space equals space straight y comma space space therefore space space 4 space sin space straight theta space dθ space equals space dy space rightwards double arrow space space space sin space straight theta space dθ space equals space 1 fourth dy
When straight theta space equals 0 comma space space straight y space equals space 5 minus 4 space cos space 0 space equals space 5 minus 4 space equals space 1
When straight theta space equals space straight pi comma space space straight y space equals space 5 minus 4 space cosπ space equals space 5 minus 4 left parenthesis negative 1 right parenthesis space equals space 5 plus 4 space equals space 9
therefore    I = 5 over 4 integral subscript 1 superscript 9 straight y to the power of 1 fourth end exponent dy space equals space 5 over 4 open square brackets fraction numerator straight y to the power of begin display style 5 over 4 end style end exponent over denominator begin display style 5 over 4 end style end fraction close square brackets subscript 1 superscript 9 space equals space open square brackets straight y to the power of 5 over 4 end exponent close square brackets subscript 1 superscript 9                                     equals left parenthesis 9 right parenthesis to the power of 5 over 4 end exponent minus 1 space equals space left parenthesis 3 squared right parenthesis to the power of 5 over 4 end exponent minus 1 space equals space 3 to the power of 5 over 2 end exponent minus 1 space equals space left parenthesis 3 to the power of 5 right parenthesis to the power of 1 half end exponent minus 1 space equals space left parenthesis 81 cross times 3 right parenthesis to the power of 1 half end exponent minus 1 space equals space 9 square root of 3 minus 1

94 Views

Advertisement
Advertisement
89.

Evaluate  integral subscript 0 superscript straight pi over 6 end superscript space cos to the power of negative 3 end exponent 2 straight theta space sin space 2 straight theta space dθ

152 Views

90.

Evaluate  space integral subscript 0 superscript 3 square root of straight pi squared end root end superscript square root of straight x space cos squared open parentheses straight x to the power of 3 over 2 end exponent close parentheses dx.

96 Views

Advertisement