Evaluate the following integral: from Mathematics Integrals

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 Multiple Choice QuestionsShort Answer Type

101.

Evaluate the following integrals
integral subscript negative 1 end subscript superscript 1 space straight x cubed space left parenthesis straight x to the power of 4 plus 1 right parenthesis cubed space dx

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102.

Evaluate the following integrals
integral subscript 0 superscript 1 straight x square root of 1 minus straight x squared end root dx

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103.

Evaluate the following integrals:
integral subscript negative 1 end subscript superscript 1 fraction numerator 5 straight x over denominator left parenthesis 4 plus straight x squared right parenthesis squared end fraction dx



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104.

Evaluate the following integral:
integral subscript 0 superscript 1 fraction numerator 5 straight x over denominator left parenthesis 4 plus straight x squared right parenthesis squared end fraction dx



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 Multiple Choice QuestionsLong Answer Type

105.

Evaluate the following integral:
integral subscript 0 superscript 2 fraction numerator dx over denominator straight x plus 4 minus straight x squared end fraction



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 Multiple Choice QuestionsShort Answer Type

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106. Evaluate the following integral:
integral subscript negative 1 end subscript superscript 1 fraction numerator dx over denominator straight x squared plus 2 straight x plus 5 end fraction


Let I = integral subscript negative 1 end subscript superscript 1 fraction numerator 1 over denominator straight x squared plus 2 straight x plus 5 end fraction dx space equals space integral subscript negative 1 end subscript superscript 1 fraction numerator 1 over denominator left parenthesis straight x squared plus 2 straight x plus 1 right parenthesis plus 4 end fraction dx
   equals space integral subscript negative 1 end subscript superscript 1 fraction numerator 1 over denominator left parenthesis straight x plus 1 right parenthesis squared plus left parenthesis 2 right parenthesis squared end fraction dx space equals space 1 half open square brackets tan to the power of negative 1 end exponent open parentheses fraction numerator straight x plus 1 over denominator 2 end fraction close parentheses close square brackets subscript negative 1 end subscript superscript 1
equals space 1 half left square bracket tan to the power of negative 1 end exponent 1 space minus space tan to the power of negative 1 end exponent 0 right square bracket space equals space 1 half open parentheses straight pi over 4 minus 0 close parentheses space equals space straight pi over 8

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107.

Evaluate integral subscript 0 superscript straight pi over 2 end superscript space square root of sin space straight ϕ end root space cos to the power of 5 straight ϕ space dϕ space

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 Multiple Choice QuestionsLong Answer Type

108.

Evaluate integral subscript 0 superscript 2 fraction numerator 5 straight x plus 1 over denominator straight x squared plus 4 end fraction dx.

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109.

Prove that: integral subscript negative straight a end subscript superscript straight a square root of fraction numerator straight a minus straight x over denominator straight a plus straight x end fraction end root space dx space equals space straight a space straight pi.

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110.

Evaluate  integral subscript 0 superscript straight pi over 2 end superscript fraction numerator sin space straight x space plus space cos space straight x over denominator square root of sinx space cosx end root end fraction dx.

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