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 Multiple Choice QuestionsShort Answer Type

171.

Evaluate  integral subscript negative 8 end subscript superscript 8 space log space open parentheses fraction numerator 2 plus straight x over denominator 2 minus straight x end fraction close parentheses dx.

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172.

Evaluate  integral subscript negative 2 end subscript superscript 2 space log space open parentheses fraction numerator 2 plus straight x over denominator 2 minus straight x end fraction close parentheses space dx.

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173.

Show that
integral subscript 0 superscript straight pi over 2 end superscript space sin squared straight x space dx space equals space straight pi over 4


Let I =  integral subscript 0 superscript straight pi divided by 2 end superscript sin squared straight x space dx                                             ...(1)
therefore space space straight I space equals space integral subscript 0 superscript straight pi divided by 2 end superscript sin squared open parentheses straight pi over 2 minus straight x close parentheses dx                     open square brackets because space space integral subscript 0 superscript straight a straight f left parenthesis straight x right parenthesis space dx space equals integral subscript 0 superscript straight a straight f left parenthesis straight a minus straight x right parenthesis space dx close square brackets
therefore space space space straight I space equals space integral subscript 0 superscript straight pi divided by 2 end superscript cos squared straight x space dx                                         ...(2)
Adding (1) and (2). we get.
          2 space straight I space equals space integral subscript 0 superscript straight pi divided by 2 end superscript left parenthesis sin squared straight x space plus cos squared straight x right parenthesis space dx space equals space integral subscript 0 superscript straight pi divided by 2 end superscript 1 space dx space equals space open square brackets straight x close square brackets subscript 0 superscript straight pi divided by 2 end superscript space equals space straight pi over 2 minus 0 space equals space straight pi over 2
therefore space space space 2 space space straight I space equals space straight pi over 2 space space space space space space space rightwards double arrow space space space space straight I space equals space straight pi over 4

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174.

By using the properties of definite integrals, evaluate the following integral:
integral subscript 0 superscript 2 straight pi end superscript cos to the power of 5 straight x space dx

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175.

Show that:
integral subscript negative straight pi over 2 end subscript superscript straight pi over 4 end superscript space sin to the power of 7 straight x space dx space equals space 0

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176.

Show that:
integral subscript negative straight pi over 4 end subscript superscript straight pi over 4 end superscript straight x cubed space space cos cubed straight x space dx space equals 0

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 Multiple Choice QuestionsLong Answer Type

177.

Evaluate integral subscript 2 superscript 3 fraction numerator square root of straight x over denominator square root of 5 minus straight x end root plus square root of straight x end fraction dx

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 Multiple Choice QuestionsShort Answer Type

178.

Evaluate integral subscript 1 superscript 4 straight f left parenthesis straight x right parenthesis space dx comma space space space where space space space straight f left parenthesis straight x right parenthesis space equals space open curly brackets table attributes columnalign left end attributes row cell 4 straight x plus 3 space if space 1 space less or equal than space straight x space less or equal than space 2 end cell row cell 3 straight x plus 5 space if space 2 space less or equal than space straight x space less or equal than space 4 end cell end table close.

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179.

Evaluate integral subscript 0 superscript straight pi over 4 end superscript space log space left parenthesis 1 plus tanx right parenthesis space dx.

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180.

Show that integral subscript 0 superscript straight pi over 2 end superscript space log space tanx space dx space equals space 0

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