Evaluate:  from Mathematics Integrals

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 Multiple Choice QuestionsShort Answer Type

231. space F i n d space colon integral fraction numerator left parenthesis 2 x minus 5 right parenthesis e to the power of 2 x end exponent over denominator left parenthesis 2 x minus 3 right parenthesis end fraction d x
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232. Find space colon integral fraction numerator straight x squared plus straight x plus 1 over denominator left parenthesis straight x squared plus 1 right parenthesis left parenthesis straight x plus 2 right parenthesis end fraction dx
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233. Evaluate space colon space integral subscript negative 2 end subscript superscript 2 fraction numerator straight x squared over denominator 1 plus 5 to the power of straight x end fraction dx.
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234. Find colon space integral left parenthesis straight x plus 3 right parenthesis square root of 3 minus 4 straight x minus straight x squared space end root space dx.
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235.

Find the integrating factor for the following differential equation:straight x space log space straight x dy over dx space plus space straight y space equals space 2 logx space

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236.

Evaluate: integral subscript 0 superscript straight pi divided by 2 end superscript fraction numerator sin squared straight x over denominator sinx plus cosx end fraction dx.

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237.

Evaluate integral subscript negative 1 end subscript superscript 2 left parenthesis straight e to the power of 3 straight x end exponent plus 7 straight x minus 5 right parenthesis dx

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238.

Evaluate:
integral fraction numerator straight x squared over denominator straight x to the power of 4 plus straight x squared minus 2 end fraction dx

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239.

Evaluate: integral fraction numerator left parenthesis straight x plus 3 right parenthesis straight e to the power of straight x over denominator left parenthesis straight x plus 5 right parenthesis cubed end fraction dx


integral fraction numerator left parenthesis straight x plus 3 right parenthesis straight e to the power of straight x over denominator left parenthesis straight x plus 5 right parenthesis cubed end fraction dx
space equals integral fraction numerator left parenthesis straight x plus 5 minus 2 right parenthesis straight e to the power of straight x over denominator left parenthesis straight x plus 5 right parenthesis end fraction dx
equals integral open square brackets fraction numerator left parenthesis straight x plus 5 right parenthesis over denominator left parenthesis straight x plus 5 right parenthesis cubed end fraction minus fraction numerator 2 over denominator left parenthesis straight x plus 5 right parenthesis cubed end fraction close square brackets straight e to the power of straight x dx
space equals integral open square brackets fraction numerator 1 over denominator left parenthesis straight x plus 5 right parenthesis squared end fraction minus fraction numerator 2 over denominator left parenthesis straight x plus 5 right parenthesis cubed end fraction close square brackets straight e to the power of straight x dx
space This space is space of space the space form
space integral straight e to the power of straight x left square bracket straight f left parenthesis straight x right parenthesis plus straight f apostrophe left parenthesis straight x right parenthesis right square bracket dx space equals space straight e to the power of straight x straight f left parenthesis straight x right parenthesis plus straight C
space space rightwards double arrow space space space integral open square brackets fraction numerator 1 over denominator left parenthesis straight x plus 5 right parenthesis squared end fraction minus fraction numerator 2 over denominator left parenthesis straight x plus 5 right parenthesis cubed end fraction close square brackets straight e to the power of straight x dx
space space space space space equals space fraction numerator straight e to the power of straight x over denominator left parenthesis straight x plus 5 right parenthesis squared end fraction plus straight C
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240.

Three schools X, Y, and Z organized a fete (mela) for collecting funds for flood victims in which they sold hand-held fans, mats and toys made from recycled material, the sale price of each being Rs. 25, Rs. 100 andRs. 50 respectively. The following table shows the number of articles of each type sold:
School/Article                     School X                   School Y                School Z
Hand-held fans                         30                         40                         35
      Mats                                  12                         15                         20
       Toys                                 70                         55                         75
Using matrices, find the funds collected by each school by selling the above articles and the total funds collected. Also write any one value generated by the above situation. 

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