∫01x321 - xdx is equal to from Mathematics In

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 Multiple Choice QuestionsMultiple Choice Questions

941.

If ft = - tte- x2dx, then limtft = ?

  • 1

  • 12

  • 0

  • - 1


942.

02πsin6xcos5xdx  = ?

  • 2π

  • π2

  • 0

  • - π


943.

If ex1 - sinx1 - cosxdx = fx + constant, then f(x) is equal to

  • excotx2 + c

  • e-xcotx2 + c

  • - excotx2 + c

  • - e- xcotx2 + c


944.

If Inxnecxdx for n  1, then cIn + n . In - 1 is equal to

  • xnecx

  • xn

  • ecx

  • xn + ecx


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945.

If ex1 + x . sec2xexdx = f(x) + constant, then f(x) is equal to

  • cosxex

  • sinxex

  • 2tan-1x

  • tanxex


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946.

01x321 - xdx is equal to

  • π6

  • π9

  • π12

  • π16


D.

π16

Let I = 01x321 - xdxPut  x = sin2θ dx = 2sinθcosθ    I = 0π2sin3θ1 - sin2θ2sinθcosθ          = 20π2sin4θcos2θ          = 23 . 1 . 16 . 4 . 2 . π2          = π16


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947.

- π2π2sinxdx is equal to

  • 0

  • 1

  • 2

  • π


948.

dxx + 14x + 3 = ?

  • tan-14x + 3 + c

  • 3tan-14x + 3 +c

  •  2tan-14x + 3 + c

  •  4tan-14x + 3 + c


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949.

2 - sin2x1 - cos2xexdx = ?

 

  • - cotx ex +c

  • cotx ex +c

  • 2cotx ex + c

  • - 2cotx ex + c


950.

If In = sinnxdx, then nIn - n - 1In - 2 = ?

  • sinn - 1xcosx

  • cosn - 1xsinx

  • - sinn - 1xcosx

  • - cosn - 1xsinx


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