Let P and Q be the points on the parabola y2 = 4x so that the line segment PQ subtends right angle at the vertex. If PQ intersects the axis of the parabola at R, then the distance of the vertex from R is
1
2
4
6
C.
4
According to question, it is given that slope of PX and QX are perpendicular to each other, i.e., slope of PX x slope of XQ = - 1
Let PQ meets axis of parabola i.e., x - axis at , then
If the three points A(1, 6), B(3,- 4) and C(x, y) are collinear, then the equation satisfying by x and y is
5x + y - 11 = 0
5x + 13y + 5 = 0
5x - 13y + 5 = 0
13x - 5y + 5 = 0
In a right-angled triangle, the sides are a, b and c with c as hypotenuse and c - b 1, c + b 1. Then the value of (logc + b(a) + logc - b(a))/ (2logc + b(a) x logc - b(a)) will be
2
- 1
1
The equation , y = 1 are the sides
an equilateral triangle
a right angled triangle
a isosceles triangle
an obtuse angled triangle
If C is a point on the line segment joining A(- 3, 4) and B(2, 1) such that AC = 2BC, then the coordinate of C is
(2, 7)
(7, 2)
A train moving with constant acceleration takes t seconds to pass a certain fixed point and the front and back end of the train pass the fixed point with velocities u and v respectively. Show that the length of the train is .
One possible condition for the three points (a, b), (b, a) and (a2, - b2) to be collinear is
a - b = 2
a + b = 2
a = 1 + b
a = 1 - b