The number of integral points (integral points means both the coordinates should be integer) exactly in the interior of the triangle with vertices (0, 0), (0, 21) and (21, 0) is
133
190
233
105
The sides AB, BC and CA of a have respectively 3, 4 and 5 points lying on them. number of triangles that can be constructed using these points as vertices is
205
220
210
None of these
P is a fixed point (a, a, a) on a line through the origin is equally inclined to the axes, then any plane through P perpendicular to Op, makes intercepts on the axes, the sum of whose reciprocal is equal to
a
None of these
B.
Since, the line is equally inclined to the axes and passes through the origin, its direction ratios are 1, 1, 1. So, its equation is .
A point P on it is given by (a, a, a). So, equation of the plane through P(a, a, a) and perpendicular to OP is
1 (x - a) + 1 (y - a) + 1 (z - a) = 0
[ OP is normal to the plane]
i.e., x + y +z = 3a
Intercepts on axes are 3a, 3a and 3a, therefore sum of reciprocals of these intercepts.
=
The tangent at (1, 7) to the curve x2 = y - 6 touches the circle x2 + y2 + 16x + 12y + c = 0 at
(6, 7)
(- 6, 7)
(6, - 7)
(- 6, - 7)
In an equilateral triangle, the inradius, circumradius and one of the exradii are in the ratio
2 : 3 : 5
1 : 2 : 3
1 : 3 : 7
3 : 7 : 9
Y-axis cuts the line joining the points (- 3, - 4) and (1, - 2) in the ratio
1 : 3
2 : 3
3 : 1
3 : 2
If the points (1, 1), (- 1, - 1), are the vertices of a triangle, then this triangle is
a right-angled triangle
an isosceles triangle
an equilateral triangle
None of the above
The point of intersection of the lines and is
(2, 10, 4)
(21, 5/3, 10/3)
(5, 7, - 2)
(- 3, 3, 6)