If 3 cot A = 4, check whether or not. from Mathematics Introdu

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8. If 3 cot A = 4, check whether
fraction numerator 1 minus tan squared straight A over denominator 1 plus tan squared straight A end fraction equals cos squared straight A space minus space sin squared straight A or not.


Let us draw a right triangle right angled at B.
We have,
3 cot A = 4
rightwards double arrow                 cotA space equals space 4 over 3 space equals space AB over BC
Let AB = 4K and BC = 3K

Let us draw a right triangle right angled at B.We have,3 cot A = 4 

Using Pythagoras theorem, we have
AC2 = AB2 + BC2
= (4K)2 + (3K)2
= 16K2 + 9K2 = 25 K2
So, AC = 5K
tan space straight A space equals space BC over AB space equals space fraction numerator 3 straight K over denominator 4 straight K end fraction space equals space 3 over 4

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#6 {main}</pre>

and sinA space equals space BC over AC equals fraction numerator 3 straight K over denominator 5 straight K end fraction space equals space 3 over 5

     L.H.S. = <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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#6 {main}</pre>

              space space equals space fraction numerator 1 minus open parentheses begin display style 3 over 4 end style close parentheses squared over denominator 1 plus open parentheses begin display style 3 over 4 end style close parentheses squared end fraction space equals space fraction numerator 1 minus begin display style 9 over 16 end style over denominator 1 plus begin display style 9 over 16 end style end fraction
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#6 {main}</pre>
Now, 
R.H.S. = cos squared straight A space minus space sin squared straight A
           equals space open parentheses 4 over 5 close parentheses squared minus open parentheses 3 over 5 close parentheses squared
equals space 16 over 25 minus 9 over 25 space equals space fraction numerator 16 minus 9 over denominator 25 end fraction space equals space 7 over 25
Hence, L.H.S. = R.H.S.
or space fraction numerator 1 minus tan squared straight A over denominator 1 plus tan squared straight A end fraction equals cos squared straight A space minus space sin squared straight A.

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#6 {main}</pre> find the value of :
(i) sin A cos C + cos A sin C 
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