Prove the following identity: from Mathematics Introduction to

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 Multiple Choice QuestionsShort Answer Type

391.

Prove the following identity:
fraction numerator cosecθ over denominator cosecθ minus 1 end fraction plus fraction numerator cosecθ over denominator cosecθ plus 1 end fraction equals 2 plus 2 tan squared straight theta.





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392.

Prove the following identity:
square root of fraction numerator 1 plus cosθ over denominator 1 minus cosθ end fraction end root equals space cosecθ plus cotθ.







straight L. straight H. straight S. space equals space square root of fraction numerator 1 plus cosθ over denominator 1 minus cosθ end fraction end root space
space space space space space space space space space space space space space equals square root of fraction numerator 1 plus cosθ over denominator 1 minus cosθ end fraction cross times fraction numerator 1 plus cosθ over denominator 1 plus cosθ end fraction end root
space space space space space space space space space space space space space equals space square root of fraction numerator left parenthesis 1 plus cosθ right parenthesis squared over denominator 1 minus cos squared straight theta end fraction end root space equals space square root of fraction numerator left parenthesis 1 plus cosθ right parenthesis squared over denominator sin squared straight theta end fraction end root
space space space space space space space space space space space space space equals space square root of open parentheses fraction numerator 1 plus cosθ over denominator sinθ end fraction close parentheses squared end root space equals space open parentheses fraction numerator 1 plus cosθ over denominator sin space straight theta end fraction close parentheses
space space space space space space space space space space space space space space equals space 1 over sinθ plus cosθ over sinθ space equals space cosecθ plus cotθ
space space space space space space space space space space space space space space equals space straight R. straight H. straight S.
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 Multiple Choice QuestionsLong Answer Type

393.

Prove the following identity:
fraction numerator tanθ over denominator 1 minus cotθ end fraction plus fraction numerator cotθ over denominator 1 minus tanθ end fraction equals 1 plus tanθ plus cotθ.







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 Multiple Choice QuestionsShort Answer Type

394.

What is the value of (Cos267o - sin2 23o)?


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395.

If 4 tan θ = 3, evaluate 4 sin θ - cos θ + 14 sin θ + cos θ - 1


396.

If tan 2A = cot (A - 18o), where 2A is an angle, find the value of A


 Multiple Choice QuestionsLong Answer Type

397.

Prove that sin A - 2sin3 A2 cos3 A - cos A = tan A.


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