Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

11. Find the values of each of the expressions

tan to the power of negative 1 end exponent open parentheses tan space fraction numerator 3 straight pi over denominator 4 end fraction close parentheses

295 Views

12. Using principle value, evaluate the following :

cos to the power of negative 1 end exponent open parentheses cos fraction numerator 2 straight pi over denominator 3 end fraction close parentheses plus sin to the power of negative 1 end exponent open parentheses sin fraction numerator 2 straight pi over denominator 3 end fraction close parentheses.

131 Views

13.

Find the value of each of the following :

(i) sin (sin^–1x + cos^–1.x) (ii) cos (sec^–1x + cosec^–1x). | x | ≥ 1

279 Views

14. Find the principal value of sin^–1

open parentheses fraction numerator 1 over denominator square root of 2 end fraction close parentheses.

121 Views

15. Find the principal value of cot^–1

open parentheses negative fraction numerator 1 over denominator square root of 3 end fraction close parentheses

161 Views

16. Find the principal values of the following

sin to the power of negative 1 end exponent open parentheses negative 1 half close parentheses

641 Views

17. Find the principal values of the following

cos to the power of negative 1 end exponent open parentheses fraction numerator square root of 3 over denominator 2 end fraction close parentheses

204 Views

18. Find the principal values of the following

cosec^-1(2)

216 Views

Let space straight y space equals space tan to the power of negative 1 end exponent left parenthesis negative square root of 3 right parenthesis space space space space space space space space space where space minus straight pi over 2 less than straight y less than straight pi over 2 therefore space space space tan space y space equals space minus square root of 3 space space space space space space space space space space space space where space minus straight pi over 2 space less than straight y less than straight pi over 2 therefore space space space tan space straight y space equals space minus tan straight pi over 3 equals tan open parentheses negative straight pi over 3 close parentheses space where space minus straight pi over 2 less than straight y less than straight pi over 2 therefore space space space space straight y equals negative straight pi over 3

therefore

required principal value =

negative straight pi over 3

204 Views

20. Find the principal values of the following

cos to the power of negative 1 end exponent open parentheses negative 1 half close parentheses

195 Views