Evaluate from Mathematics Inverse Trigonometric Functions

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 Multiple Choice QuestionsShort Answer Type

21. Find the principal values of the following

tan-1(- 1)


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22. Find the principal values of the following

sec to the power of negative 1 end exponent open parentheses fraction numerator 2 over denominator square root of 3 end fraction close parentheses


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23. Find the principal values of the following

cot to the power of negative 1 end exponent open parentheses square root of 3 close parentheses


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24. Find the principal values of the following

cos to the power of negative 1 end exponent open parentheses negative fraction numerator 1 over denominator square root of 2 end fraction close parentheses


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25. Find the principal values of the following

cos e c to the power of negative 1 end exponent left parenthesis negative square root of 2 right parenthesis


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26. Evaluate

sin open square brackets 2 space cos to the power of negative 1 end exponent open parentheses negative 3 over 5 close parentheses close square brackets


Let space straight y equals cos to the power of negative 1 end exponent open parentheses negative 3 over 5 close parentheses
therefore space space space cos space straight y equals negative 3 over 5 space and space straight y element of space left square bracket 0 comma space straight pi right square bracket
therefore space space space sin space straight y space is space plus space ve
sin space straight y space equals space square root of 1 minus cos squared end root space straight y equals square root of 1 minus open parentheses negative 3 over 5 close parentheses squared end root equals square root of 1 minus 9 over 25 end root equals 4 over 5

Not given expression = 

sin open square brackets 2 space cos to the power of negative 1 end exponent open parentheses negative 3 over 5 close parentheses close square brackets equals space s n space left square bracket 2 space y right square bracket space equals space 2 space sin space y space cos space y equals 2 open parentheses 4 over 5 close parentheses open parentheses negative 3 over 5 close parentheses equals negative 24 over 25 space space space space space
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27. Evaluate  sin[ tan-1 (- 1) ]



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28. Find the value of tan-1 open square brackets 2 space cos space open parentheses 2 space sin to the power of negative 1 end exponent 1 half close parentheses close square brackets
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29. Find the value of the following :

space space space space space space space space tan to the power of negative 1 end exponent left parenthesis 1 right parenthesis plus cos to the power of negative 1 end exponent open parentheses negative 1 half close parentheses plus sin to the power of negative 1 end exponent open parentheses negative 1 half close parentheses
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30. Find the value of the following :

cos to the power of negative 1 end exponent open parentheses 1 half close parentheses plus 2 space sin to the power of negative 1 end exponent open parentheses 1 half close parentheses
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