Simplify from Mathematics Inverse Trigonometric Functions

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 Multiple Choice QuestionsShort Answer Type

81.

Write tan to the power of negative 1 end exponent open parentheses fraction numerator 1 over denominator square root of straight x squared minus 1 end root end fraction close parentheses comma space open vertical bar straight x close vertical bar space greater than space 1 in the simplest form.

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82.

Write tan to the power of negative 1 end exponent open square brackets fraction numerator 3 straight a squared space straight x minus straight x cubed over denominator straight a left parenthesis straight a cubed minus 3 straight x squared right parenthesis end fraction close square brackets comma space straight a greater than 0 comma space space minus fraction numerator straight a over denominator square root of 3 end fraction less or equal than straight x less or equal than fraction numerator straight a over denominator square root of 3 end fraction in the simplest form.

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83. Write the following in the simplest form : 

cot to the power of negative 1 end exponent open parentheses fraction numerator 1 over denominator square root of straight x squared minus 1 end root end fraction close parentheses comma space open vertical bar straight x close vertical bar greater than 1
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84. Write the following in the simplest form :tan to the power of negative 1 end exponent open parentheses fraction numerator straight x over denominator square root of straight a squared minus straight x squared end root end fraction close parentheses comma space open vertical bar straight x close vertical bar less than straight a


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85. Write the following in the simplest form :

tan to the power of negative 1 end exponent open square brackets square root of fraction numerator 1 minus cos space straight x over denominator 1 plus sin space straight x end fraction end root close square brackets

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86. Write the following in the simplest form :

tan to the power of negative 1 end exponent open parentheses fraction numerator cos space straight x minus sin space straight x over denominator cos space straight x plus sin space straight x end fraction close parentheses

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87. Simplify

cos to the power of negative 1 end exponent open square brackets square root of fraction numerator 1 plus cos space 3 x over denominator 1 minus cos space 3 x end fraction end root close square brackets


Let space space space space straight z equals cot to the power of negative 1 end exponent open square brackets square root of fraction numerator 1 plus cos space 3 straight x over denominator 1 minus cos space 3 straight x end fraction end root close square brackets
therefore space space space space straight z equals cot to the power of negative 1 end exponent open square brackets square root of fraction numerator 2 space cos squared begin display style 3 over 2 end style straight x over denominator 2 space sin squared space begin display style 3 over 2 end style straight x end fraction end root close square brackets equals cot to the power of negative 1 end exponent open parentheses cot 3 over 2 straight x close parentheses equals 3 over 2 straight x
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88. Simplify

tan to the power of negative 1 end exponent open parentheses fraction numerator square root of 1 plus x squared end root minus 1 over denominator x end fraction close parentheses
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89. Simplify

tan to the power of negative 1 end exponent open parentheses fraction numerator square root of 1 plus x squared end root minus 1 over denominator x end fraction close parentheses
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90. Simplify

cot to the power of negative 1 end exponent open parentheses square root of 1 plus straight x squared end root minus straight x close parentheses
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