Prove that  from Mathematics Inverse Trigonometric Functions

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 Multiple Choice QuestionsShort Answer Type

111.

Write the value of open parentheses 2 tan to the power of negative 1 end exponent 1 fifth close parentheses

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112.

Find the value of the following:
tan 1 half open square brackets sin to the power of negative 1 end exponent fraction numerator 2 straight x over denominator 1 plus straight x squared end fraction plus cos to the power of negative 1 end exponent fraction numerator 1 minus straight y squared over denominator 1 plus straight y squared end fraction close square brackets comma space open vertical bar straight x close vertical bar space less than 1 comma space space straight y greater than 0 space and space xy less than 1

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113.

Prove that tan to the power of negative 1 end exponent open parentheses 1 half close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 fifth close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 over 8 close parentheses space equals straight pi over 4


We know that:
tan to the power of negative 1 end exponent straight x plus tan to the power of negative 1 end exponent straight y space equals space tan to the power of negative 1 end exponent fraction numerator straight x plus straight y over denominator 1 minus xy end fraction comma space xy less than 1
We have:
tan to the power of negative 1 end exponent open parentheses 1 half close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 fifth close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 over 8 close parentheses
equals open square brackets tan to the power of negative 1 end exponent open parentheses 1 half close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 fifth close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 over 8 close parentheses close square brackets
equals tan to the power of negative 1 end exponent open parentheses fraction numerator begin display style 1 half end style plus begin display style 1 fifth end style over denominator 1 minus begin display style 1 half end style cross times begin display style 1 fifth end style end fraction close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 over 8 close parentheses space space space open parentheses because space space 1 half cross times 1 fifth less than 1 close parentheses
equals tan to the power of negative 1 end exponent open parentheses 7 over 9 close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 over 8 close parentheses
equals tan to the power of negative 1 end exponent fraction numerator begin display style 7 over 9 end style plus begin display style 1 over 8 end style over denominator 1 minus begin display style 7 over 9 end style cross times begin display style 1 over 8 end style end fraction
equals tan to the power of negative 1 end exponent fraction numerator 56 plus 9 over denominator 72 minus 7 end fraction space open parentheses because 7 over 9 cross times 1 over 8 less than 1 close parentheses
equals tan to the power of negative 1 end exponent 65 over 65 equals tan to the power of negative 1 end exponent 1 equals straight pi over 4
Hence comma space tan to the power of negative 1 end exponent open parentheses 1 half close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 fifth close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 over 8 close parentheses equals straight pi over 4


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114.

If a line makes angles 90° and 60° respectively with the positive directions of x and y axes, find the angle which it makes with the positive direction of the z-axis.

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115.
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116.

Prove that 

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117.

Find the value of tan-1 3 - cot-1 (-3)


118.

Prove that:3 sin-1 x  = sin-1 (3x - 4x3), X  -12, 12


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119.

Evaluate:   sinπ3 - sin-1 12


 Multiple Choice QuestionsLong Answer Type

120.

Prove the following:

tan-113 + tan-115 + tan-117 + tan-118


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