If sin-1x - cos-1x = π6, then x is equal to
12
32
- 12
- 32
B.
We havesin-1x - cos-1x = π6Let A = sin-1x⇒ x= sinAcosA = 1 - x2and B = cos-1x⇒ x= sinBcosB = 1 - x2Now, sinA - B = sinAcosB - cosAsinB = x x - 1 - x21 - x2 = x2 - 1 + x2sinπ6 = 2x2 - 1⇒2x2 - 1 = 12 ⇒ 2x2 = 32 ⇒x2 = 34⇒ x = 32
sinh-1232 is equal to
log3 + 8
log3 - 8
log2 + 18
log8 + 27
coscos-1- 1 7 + sin-1- 17 is equal to
- 13
0
13
49
If sin-1x + sin-11 - x = cos-1x, then x ∈ to
{1, 0}
{- 1, 1}
0, 12
{2, 0}
sin-145 + 2tan-113 is equal to
π3
π4
π2
2tanh-112 is equal to
log(2)
log(3)
log(4)
The cartesian form of the polar equation θ = tan-12 is
x = 2y
y = 2x
x = 4y
y = 4x
The value of x, where x > 0and tansec - 11x = sintan-12 is
5
53
1
23
If sin-13x + sin-14x = π2, then x = ?
3
7
11
cos-1- 12 - 2sin-112 +3cos-1- 12 - 4tan-1- 1 = ?
19π12
35π12
47π12
43π12