tan-1x2 + cot-1x2 = 5π28 ⇒ 

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 Multiple Choice QuestionsMultiple Choice Questions

311.

sinh-12 + sinh-13 = x  coshx =  ?

  • 1235 + 210

  • 1235 - 210

  • 1212 + 250

  • 1212 - 250


312.

In any ABC, abcosC - ccosB = ?

  • b2 + c2

  • b2 - c2

  • 1b + 1c

  • 1b2 - 1c2


313.

If tan-1x + tan-1y + tan-1z = π2, then 1 - xy - yz - zx = ?

  • 1

  • 0

  • - 1

  • 2


314.

If tanh-1x = alog1 + x1 - x, x < 1, then a = ?

  • 1

  • 2

  • 12

  • 14


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315.

tan-1x2 + cot-1x2 = 5π28  x = 

  • - 1

  • 1

  • 0

  • π58


A.

- 1

Given equation istan-1x2 + cot-1x2 = 5π28 tan-1x2 + cot-1x2 - 2tan-1xcot-1x = 5x28 tan-1x + cot-1x = π2  π24 - 2tan-1xπ2 - tan-1x = 5π28 - 2 . πtan-1x2 + 2tan-1x2 = 5π28 - π24 tan-1x2 - πtan-1x2 = 3π216 tan-1x = π2 ± π24 + 3π242 tan-1x = π2 ± π2                   = 3π4, - π4 x = tan3π4, tan- π4 x = - 1, - 1


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316.

For 0 < x  π, sinh-1cotx = ?

  • logcotx2

  • logtanx2

  • log1 + cotx

  • log1 + tanx


317.

If 12  x  1, thencos-1x + cos-1x2 + 123 - 3x2 = ?

  • π6

  • π3

  • π

  • 0


318.

If cos-1513 + cos-135 = cos-1x, then x = ?

  • 363

  • - 3665

  • - 3365

  • - 1


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319.

tanh-112 + coth-12 = ?

  • 13log3

  • 12log6

  • 12log12

  • log3


320.

If x > 0, y > 0, z > 0, xy + yz + zx < 1 and if tan-1x + tan-1y + tan-1z = π, then x + y +z =?

  • 0

  • xyz

  • 3xyz

  • xyz


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