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 Multiple Choice QuestionsMultiple Choice Questions

321.

sech-112 - cosec-134 = ?

  • loge32 + 3

  • loge1 + 33

  • loge2 + 33

  • loge2 - 33


322.

If sin-1x - x22 + x34 - . ...  + cos-1x2 - x42 + x64 - . ...  = π2 and 0 < x < 2, then x is equal to

  • 12

  • 1

  • - 12

  • - 1


323.

If 2sinh-1a1 - a2 = log1 + x1 - x, then x is equal to

  • a

  • 1a

  • 1 - a2

  • 11 - a2


324.

If x =sin2tan-12 and y = sin12tan-143, then

  • x > y

  • x = y

  • x = 0 = y

  • x< y


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325.

If coshx = 54, then cosh3x = ?

  • 6116

  • 6316

  • 6516

  • 6163


326.

In aABC, if <A = 90°, then cos-1Rr2 +r3 = ?

  • 90°

  • 30°

  • 60°

  • 45°


327.

If cotcos-1x = sectan-1ab2 - a2 : b > a, then x = 

  • b2b2 - a2

  • b2 - a2ab

  • a2b2 - a2

  • b2 - a2a


328.

2π - sin-145 + sin-1513 + sin-11665 = ?

  • π2

  • π

  • 3π2

  •  - π2


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329. tan to the power of negative 1 end exponent open parentheses straight x over straight y close parentheses minus tan to the power of negative 1 end exponent fraction numerator straight x minus straight y over denominator straight x plus straight y end fraction is space equal space to
  • straight pi over 2
  • straight pi over 3
  • straight pi over 4
  • straight pi over 4


tan to the power of negative 1 end exponent open parentheses x over y close parentheses minus tan to the power of negative 1 end exponent open parentheses fraction numerator x minus y over denominator x plus y end fraction close parentheses equals tan to the power of negative 1 end exponent open parentheses x over y close parentheses minus tan to the power of negative 1 end exponent open parentheses fraction numerator begin display style x over y end style minus 1 over denominator begin display style x over y end style plus 1 end fraction close parentheses
space space space space space space space space space space space space space space space space space equals tan to the power of negative 1 end exponent open parentheses x over y close parentheses minus open curly brackets tan to the power of negative 1 end exponent x over y minus tan to the power of negative 1 end exponent space 1 close curly brackets equals tan to the power of negative 1 end exponent space 1 equals straight pi over 4
∴ (C) is correct answer.
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330. sin to the power of negative 1 end exponent left parenthesis 1 minus x right parenthesis minus 2 space sin to the power of negative 1 end exponent space x comma space equals straight pi over 2 comma space then x is equal to
  • 0 comma 1 half
  • 1 comma 1 half
  • 0

  • 0

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