then x is equal to from Mathematics Inverse Trigonometric Fun

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

321.

sech-112 - cosec-134 = ?

  • loge32 + 3

  • loge1 + 33

  • loge2 + 33

  • loge2 - 33


322.

If sin-1x - x22 + x34 - . ...  + cos-1x2 - x42 + x64 - . ...  = π2 and 0 < x < 2, then x is equal to

  • 12

  • 1

  • - 12

  • - 1


323.

If 2sinh-1a1 - a2 = log1 + x1 - x, then x is equal to

  • a

  • 1a

  • 1 - a2

  • 11 - a2


324.

If x =sin2tan-12 and y = sin12tan-143, then

  • x > y

  • x = y

  • x = 0 = y

  • x< y


Advertisement
325.

If coshx = 54, then cosh3x = ?

  • 6116

  • 6316

  • 6516

  • 6163


326.

In aABC, if <A = 90°, then cos-1Rr2 +r3 = ?

  • 90°

  • 30°

  • 60°

  • 45°


327.

If cotcos-1x = sectan-1ab2 - a2 : b > a, then x = 

  • b2b2 - a2

  • b2 - a2ab

  • a2b2 - a2

  • b2 - a2a


328.

2π - sin-145 + sin-1513 + sin-11665 = ?

  • π2

  • π

  • 3π2

  •  - π2


Advertisement
329. tan to the power of negative 1 end exponent open parentheses straight x over straight y close parentheses minus tan to the power of negative 1 end exponent fraction numerator straight x minus straight y over denominator straight x plus straight y end fraction is space equal space to
  • straight pi over 2
  • straight pi over 3
  • straight pi over 4
  • straight pi over 4
82 Views

Advertisement

330. sin to the power of negative 1 end exponent left parenthesis 1 minus x right parenthesis minus 2 space sin to the power of negative 1 end exponent space x comma space equals straight pi over 2 comma space then x is equal to
  • 0 comma 1 half
  • 1 comma 1 half
  • 0

  • 0


C.

0

Here sin-1(1 - x)-2 sin-1 x=straight x over 2

therefore space space space minus 2 space sin to the power of negative 1 end exponent space straight x equals straight pi over 2 minus sin to the power of negative 1 end exponent left parenthesis 1 minus straight x right parenthesis space space space space rightwards double arrow space minus 2 space sin to the power of negative 1 end exponent space straight x equals cos to the power of negative 1 end exponent left parenthesis 1 minus straight x right parenthesis
rightwards double arrow space space cos left parenthesis negative 2 space sin to the power of negative 1 end exponent space straight x right parenthesis equals 1 minus straight x space space space space space space space space space space space space space space rightwards double arrow space cos left parenthesis 2 space sin to the power of negative 1 end exponent space straight x right parenthesis equals 1 minus straight x
rightwards double arrow space space left square bracket 1 minus 2 sin squared left parenthesis sin to the power of negative 1 end exponent space straight x right parenthesis equals 1 minus straight x space space space space space space space space space space space space space space space left square bracket because space cos space 2 space straight theta equals 1 minus 2 space sin squared space straight theta space right square bracket
rightwards double arrow space space 1 minus 2 straight x squared equals 1 minus straight x space space space rightwards double arrow space 2 space straight x squared minus straight x equals 0
rightwards double arrow space space space straight x left parenthesis 2 space straight x minus 1 right parenthesis equals 0 space space rightwards double arrow space straight x equals 0 comma space 1 half
But 1 half does not satisfy the given equation.
                                 open square brackets because space space sin to the power of negative 1 end exponent open parentheses 1 minus 1 half close parentheses minus 2 space sin to the power of negative 1 end exponent open parentheses 1 half close parentheses equals straight pi over 6 minus 2 cross times straight pi over 6 not equal to straight pi over 2 close square brackets
therefore space space space space space space space space space space space space space space space x equals 0
                         

80 Views

Advertisement
Advertisement