For the function :Â Prove that f(1) = 100 f'(0)
Here, Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
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L.H.S. Â = f(1) = (1)99Â + (1)98Â + ....... +(1)1Â + 1 = 1+1+ ....+1+1 = 100
R.H.S. = [100f'(0) = 100(0)99Â +(0)98Â + ..... + (0)1Â +1] = 100
∴ L.H.S =R.H.S.
Hence, Â f'(1) = 100 f'(0)