Solve the following linear equation:
∵ LCM of 4 and 3 is 12.
∴ Multiplying both sides by 12, we have
or 3(3t-2) - 4(2t+3) = (4 2) - 12t
or 9t - 6 - 8t - 12 = 8 - 12t
or (9-8)t - (6+12) = 8 - 12t
or t-18 = 8 - 12t
Transposing -18 to RHS and -12t to LHS, we have
t +12t = 8 + 18
or 13t = 26
or (Dividing both sides by 2)
∴ t = 2
Check: LHS =
=
=
=
=
RHS =
=
=
∴ LHS = RHS
Simplify and solve the following linear equation:
3(5z - 7) - 2(9z - 11) = 4(8z - 13) - 17