Solve for from Mathematics Linear Equations in One Variable

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 Multiple Choice QuestionsShort Answer Type

111.

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112.

Solve for straight x colon fraction numerator 7 straight x plus 14 over denominator 3 end fraction minus fraction numerator 17 minus 3 straight x over denominator 5 end fraction equals 6 straight x minus fraction numerator 4 straight x plus 2 over denominator 3 end fraction minus 5


We have fraction numerator 7 straight x plus 14 over denominator 3 end fraction minus fraction numerator 17 minus 3 straight x over denominator 5 end fraction equals 6 straight x minus fraction numerator 4 straight x plus 2 over denominator 3 end fraction minus 5

   Since, LCM of 3 and 5 is 15.

∴      The given equation is expressed as:

          space space fraction numerator 5 left square bracket 7 x plus 14 right square bracket over denominator 5 cross times 3 end fraction minus fraction numerator 3 left square bracket 17 minus 3 x right square bracket over denominator 3 cross times 5 end fraction equals open parentheses fraction numerator 15 cross times 6 x over denominator 15 end fraction close parentheses minus fraction numerator 5 left parenthesis 4 x plus 2 right parenthesis over denominator 5 cross times 3 end fraction minus open parentheses fraction numerator 15 cross times 5 over denominator 15 end fraction close parentheses

rightwards double arrow          fraction numerator 35 straight x plus 70 over denominator 15 end fraction minus fraction numerator left parenthesis 51 minus 9 straight x right parenthesis over denominator 15 end fraction equals fraction numerator 90 straight x over denominator 15 end fraction minus fraction numerator left parenthesis 20 straight x plus 10 right parenthesis over denominator 15 end fraction minus 75 over 15

rightwards double arrow           35x + 70 - (51-9x) = 90x - (20x + 10) - 75

rightwards double arrow              35x + 70 -51 + 9x = 90x - 20x - 10 - 75

rightwards double arrow            35x + 9x - 90x + 20x = -10 -75 + 51 - 70

rightwards double arrow                        64x - 90x = -155 + 51

rightwards double arrow                             -26x = -104

rightwards double arrow                               straight x equals fraction numerator negative 104 over denominator negative 26 end fraction equals 4

   Thus, x = 4 is the solution of the given equation.

  





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113.

Solve for space space space space straight x colon fraction numerator straight x minus left parenthesis 7 minus 8 straight x right parenthesis over denominator 9 straight x minus left parenthesis 3 plus 4 straight x right parenthesis end fraction equals 2 over 3

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114.

Solve for straight x colon fraction numerator left parenthesis 2 plus straight x right parenthesis left parenthesis 7 minus straight x right parenthesis over denominator left parenthesis 5 minus straight x right parenthesis left parenthesis 4 plus straight x right parenthesis end fraction equals 1

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115.

A number is such that it is as much greater than 65 as it is less than 91. Find the number.

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116.

The numerator of a fraction is 2 less than the denominator. If 1 is added to its denominator, it becomes ½. Find the fraction.

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117.

After 24 years I shall be 3 times as old as I was 4 years ago. Find my present age.

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118.

If the sum of two numbers is 30 and their ratio is 2 : 3, then find the numbers.

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119.

Solve for x:

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120.

Solve for x:

fraction numerator straight x minus 3 over denominator straight x plus 1 end fraction equals 1 half

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