Consider the line 2x + y = 2. Clearly, the shaded portion and the origin are on the opposite sides of the graph. So, we have its inequality as:
                                    [∵ 2(0) + 0 ≥ 2 is not true]
Now, consider the line x + 2y = 8.
Origin and shaded region are on the same side of the line x + 2y = 8.
So, its inequality is:
                                     [∵ 0 + 2(0) ≤ 8 is true]
Finally, consider the line x - y = 1
Origin and shaded region are on the same side.
So, its inequality is:
                                       [∵ 0 - 0 ≤ 1 is true]
Also,          x ≥ 0 and y ≥ 0
Thus, the linear inequalities are:
2x + y ≥ 2,  x + 2y ≤ 8, x - y ≤ 1, x ≥ 0 and y ≥ 0
Solving the following inequalities. Also represent the solutions on the number line.
3x - 2 > x + 5
Solving the following inequalities. Also represent the solutions on the number line.
-4x + 1 ≤ 2 (1 - x)
Solve the following system of simultaneous linear inequality and represent its solution on the number line.
2x + 3 < x - 1 and x + 4 > 2x - 3
Solve the following system of simultaneous linear inequality and represent its solution on the number line.
-3x + 2 ≥ 0 and 2 - x < 0