The corner points of the feasible region determined by the following system of linear inequalities:
2x + y ≤ 10, x + 3y ≤ 15, x, y ≥ 0 are (0, 0), (5, 0), (3, 4) and (0, 5). Let Z = px + qy, where p, q > 0. Condition on p and q so that the maximum of Z occurs at both (3, 4) and (0, 5) is
A dietician has to develop a special diet using two foods P and Q. Each packet (containing 30 g) of food P contains 12 units of calcium, 4 units of iron, 6 units of cholesterol and 6 units of vitamin A. Each packet of the same quantity of food Q contains 3 units of calcium, 20 units of iron, 4 units of cholesterol and 3 units of vitamin A. The diet requires at least 240 units of calcium, at least 460 units of iron and at most 300 units of cholesterol. How many packets of each food should be used to minimise the amount of vitamin A in the diet? What is the minimum amount of vitamin A?
How many packets of each food should be used to maximise the amount of vitamin A in the diet? What is the maximum amount of vitamin A in the diet?
Let x and y be the number of packets of food P and Q respectively. Clearly x ≥ 0, y ≥ 0.
Let Z be the quantity used of vitamin A.
Mathematical formulation of the given problem is as follows:
Minimise Z = 6x + 3y
subject to the constraints
12x + 3y ≥ 240 i.e. 4 x + y ≥ 80
4x + 20y ≥ 460 i.e. x + 5 y ≥ 115
6x + 4y ≤ 300 i.e. 3 x + 2 y ≤ 150
x ≥ 0, y ≥ 0
Consider a set of rectangular cartesian axes OXY in the plane.
It is clear that any point which satisfies x ≥ 0, y ≥ 0 lies in the first quadrant.
Now we draw the graph of 4x + y = 80
For x = 0, y = 80
For y = 0, 4 x = 80 or x = 20
∴ line meets OX in A(20, 0) and OY in L(0, 80).
Also we draw the graph of x + 5y = 115
For x = 0, 5y = 115 or y = 23
For y = 0, x = 115
∴ line meets OX in E (115, 0) and OY in M(0, 23)
Again consider
3x + 2y = 150
For x = 0, 2 y = 150 or y = 75
For y = 0, 3 x = 150 or x = 50
∴ line meets OX in C(50, 0) and OY in N (0, 75).
Since feasible region satisfies all the constraints.
∴ DEF is the feasible region.
The corner points are D(40, 15), E(15, 20), F(2, 72).
At D(40, 15), Z = 6 × 40 + 3 × 15 = 240 + 45 = 285
At E(15, 20), Z = 6 × 15 + 3 × 20 = 90 + 60 = 150
At F(2, 72), Z = 6 × 2 + 3 × 72 = 12 + 216 = 228
∴ minimum value = 150 at (15, 20).
∴ the amount of vitamin A under the constraints given in the problem will be minimum, if 15 packets of food P and 20 packets of food Q are used in the speciai diet. The minimum amount of vitamin A will be 150 units.
Now instead of minimising Z, we have to maximise Z.
∴ maximum value = 285 at (40, 15)
∴ the amount of vitamin A under the constraints given in the problem will be maximum, if 40 packets of focd P and 15 packets of food Q are used in the special diet. The maximum amount of vitamin A will be 285 units.
A manufacturer has three machines 1, II and III installed in his factory. Machines I and II are capable of being operated for at most 12 hours whereas machine III must be operated for at least 5 hours a day. She produces only two items M and N each requiring the use of all the three machines.
The number of hours required for producing 1 unit of each of M and N on the three machines are given in the following table:
Items |
Number of 1 |
ours required |
on machines |
I |
II |
III |
|
M |
1 |
2 |
1 |
N |
2 |
1 |
1.25 |
She makes a profit of Rs. 600 and Rs. 400 on items M and N respectively. How many of each item should she produce so as to maximise her profit assuming that she can sell all the items that she produced? What will be the maximum profit?
A manufacturer makes two types of toys A and B. Three machines are needed for this purpose and the time (in minutes) requires for each toy on the machines is given below:
Types of Toys |
Machines |
||
I |
II |
III |
|
A |
12 |
18 |
6 |
B |
6 |
0 |
9 |
Each machine is available for a maximum of 6 hours per day. If the profit on each toy of type A is Rs. 7.50 and that on each toy of type B is Rs. 5, show that 15 toys of type A and 30 of type B should be manufactured in a day to get maximum profit.
Two godowns A and B have grain capacity of 100 quintals and 50 quintals respectively. They supply to 3 ration shops, D, E and F whose requirements arc 60, 50 and 40 quintals respectively. The cost of transportation per quintal from the godowns to the shops arc given in the following table:
Transportation cost per quintal (in Rs.) |
||
From/To |
A |
B |
D |
6 |
4 |
E |
3 |
2 |
F |
2.50 |
3 |
How should the supplies be transported in order that the transportation cost is minimum ? What is the minimum cost?
A fruit grower can use two types of fertilizer in his garden, brand P and brand Q. The amounts (in kg.) of nitrogen, phosphoric acid, potash, and chlorine in a bag of each brand are given in the table. Tests indicate that the garden needs at least 240 kg of phosphoric acid, at least 270 kg. of potash and at most 310 kg. of chlorine.
If the grower wants to minimise the amount of nitrogen added to the garden, how many bags of each brand should be used? What is the minimum amount of nitrogen added in the garden?
kg. per bag |
||
Brand P |
Brand Q |
|
Nitrogen |
3 |
3.5 |
Phosphoric acid |
1 |
2 |
Potash |
3 |
1.5 |
Chlorine |
1.5 |
2 |
If the grower wants to maximise the amount of nitrogen added in the garden, how many bags of each brand should be added? What is the maximum amount of nitrogen added?
There are two factories located one at place P and the other at place Q. From these locations, a certain commodity is to be delivered to each of the three depots situated at A, B and C. The weekly requirements of the depots are respectively 5, 5 and 4 units of the commodity while the production capacity of the factories at P and Q are respectively 8 and 6 units The cost of transportation per unit is given below:
From/To |
Cost (in Rs.) |
||
A |
B |
C |
|
P |
160 |
100 |
150 |
Q |
100 |
120 |
100 |
How many units should be transported from each factory to each depot in order that the transportation cost is minimum. What will be the minimum transportation cost?
An oil company has two depots A and B with capacities of 7000 L and 4000 L respectively. The company is to supply oil to three petrol pumps, D. E and F whose requirements are 4500 L, 3000 L and 3500 L respectively. The distance (in km.) between the depots and the petrol pumps are given in the following table:
Distance (in km.) |
||
From/To |
A |
B |
D |
7 |
3 |
E |
6 |
4 |
F |
3 |
2 |
Assuming that the transportation cost of 10 litres of oil is Re 1 per km., how should the delivery be scheduled in order that the transportation cost is minimum? What is the minimum cost?