In figure, if PQ || ST, ∠PQR = 110° and ∠RST = 130°, find ∠QRS.
[Hint. Draw a line parallel to ST through point R.]
In figure, EF is a transversal to two parallel lines AB and CD, GM and HL are the bisectors of the corresponding angles EGB and EHD. Prove that GM || HL.
[Hint. First prove that ∠EGM = ∠GHL]
Construction: Through O draw OE || AB || CD
Now, y = ∠FOG
= ∠FOE + ∠GOE
= ∠CFO + ∠AGO
∠FOE = ∠CFO
(Alternate Interior Angles)
∠GOE = ∠AGO (Alternate Interior Angles)
= 45° + 40°
= 85°
In figure, PQ || RS and T is any point as shown in the figure then show that
∠PQT + ∠QTS + ∠RST = 360°.