Short Answer TypeIn figure, if PQ || ST, ∠PQR = 110° and ∠RST = 130°, find ∠QRS.
[Hint. Draw a line parallel to ST through point R.]
In figure, EF is a transversal to two parallel lines AB and CD, GM and HL are the bisectors of the corresponding angles EGB and EHD. Prove that GM || HL.
[Hint. First prove that ∠EGM = ∠GHL]
In figure, PQ || RS and T is any point as shown in the figure then show that
∠PQT + ∠QTS + ∠RST = 360°.
Given: l, m, n are three lines such that l || m and n ⊥ l.
To Prove: n ⊥ m
Proof: ∵ l || m and n is a transversal
∵ ∠1 = ∠2 | Corresponding angles
But ∠1 = 90° | ∵ n ⊥ l (given)
∴ ∠2 = 90°
⇒ n ⊥ m
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