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Mathematics : Matrices

Short Answer Type

41. Compute the following :

open square brackets table row cell negative 1 end cell 4 cell negative 6 end cell row 8 5 16 row 2 8 5 end table close square brackets plus open square brackets table row 12 7 6 row 8 0 5 row 3 2 4 end table close square brackets

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42. Compute the following :

open square brackets table row cell cos squared straight x end cell cell sin squared straight x end cell row cell sin squared straight x end cell cell cos squared straight x end cell end table close square brackets plus open square brackets table row cell sin squared x end cell cell cos squared x end cell row cell cos squared x end cell cell sin squared x end cell end table close square brackets

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43.

If $straight A equals open square brackets table row 1 4 cell negative 1 end cell row 2 6 5 end table close square brackets space and space straight B equals open square brackets table row 3 cell negative 2 end cell cell negative 6 end cell row 2 0 cell negative 7 end cell end table close square brackets$ , find A + B and A - B.

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44.

If $straight A equals open square brackets table row 1 2 cell negative 3 end cell row 5 0 2 row 1 cell negative 1 end cell 1 end table close square brackets comma space straight B equals open square brackets table row 3 cell negative 1 end cell 2 row 4 2 5 row 2 0 3 end table close square brackets space and space straight C equals open square brackets table row 4 1 2 row 0 3 3 row 1 cell negative 2 end cell 3 end table close square brackets.$ compute (A + B) and (B – C). Also verify that A+ (B – C) = (A + B) – C.

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45. If

straight A equals open square brackets table row 1 2 3 row 2 3 1 end table close square brackets space and space straight B equals open square brackets table row 3 cell negative 1 end cell 3 row cell negative 1 end cell 0 2 end table close square brackets

, then find 2A - B.

88 Views

Long Answer Type

46.

$If space space straight A equals open square brackets table row cell 2 over 3 end cell 1 cell 5 over 3 end cell row cell 1 third end cell cell 2 over 3 end cell cell 4 over 3 end cell row cell 7 over 3 end cell 2 cell 2 over 3 end cell end table close square brackets space and space straight B space equals open square brackets table row cell 2 over 5 end cell cell 3 over 5 end cell 1 row cell 1 fifth end cell cell 2 over 5 end cell cell 4 over 5 end cell row cell 7 over 5 end cell cell 6 over 5 end cell cell 2 over 5 end cell end table close square brackets$ then computer 3A-5B