Here
Now, A = B
∴ by the definition of equality of matrices.
2 x + 1 = .x + 3, 3 y = + 2 , y2 –5 y = – 6
Now 2 x + I = x + 3 ⇒ x= 2
3 x = y2 +2 ⇒ y2 -3 y + 2 = 0 ⇒ ( y –1) (y – 2) = 0 ⇒ y = I, 2
y2 –5 y =-6 ;⇒ -5 y + 6 = 0 ;⇒ (y–2)(y–3) = 0 ;⇒ y = 2.3
Since both the equations 3 y = y2 +2 and y2 –5 y = – 6 arc to be satisfied
simultaneously, so we have y = 2.
∴A – B when x = 2, y – 2.
Not possible to find
The number of all possible matrices of order 3 x 3 with each entry 0 or 1 is.
27
18
81
81