Find the area of a rhombus whose diagonals are 12 cm and 9.2 cm.

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14. Find the area of a rhombus whose diagonals are 12 cm and 9.2 cm.


Let straight d subscript 1 space and space straight d subscript 2 be the diagonals of the rhombus.
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#6 {main}</pre> and straight d subscript 2 space equals space 9.2 space space cm

∵                       Area of rhombus = space 1 half cross times straight d subscript 1 cross times straight d subscript 2
∴       Area of the given rhombus = 1 half cross times 12 cross times 9.2 space cm squared
                                                  space space equals space 6 cross times 9.2 space cm squared space equals space 55.2 space cm squared
 
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Polygon ABCDE is divided into parts as shown below. Find its area of AD = 8 cm, AH = 6 cm, AG = 4 cm, AF = 3 cm and perpendiculars BF = 2 cm, CH = 3 cm, EG = 2.5 cm.

  Area of polygon ABCDE = Area of straight capital delta space AFB + .........

Area of increment space AFB = 1 half cross times AF cross times BF space equals space 1 half cross times 3 cross times 2 space equals space..........

Area of trapezium FBCH =  FH cross times fraction numerator left parenthesis BF plus CH right parenthesis over denominator 2 end fraction

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#6 {main}</pre>

Area of increment space CHD space equals space 1 half cross times HD cross times CH space equals space........

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#6 {main}</pre>
So, the area of polygon ABCDE = ........

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