The edge (side) of the given cube = 2 cm
Since, there such cubes are joined, then
Total length (l) = (2+2+2) cm
= 6 cm
Breadth (b) = 2 cm
Height (h) = 2 cm
∴ Total surface area of the resultant cuboid
= 2[lb + bh + hl]
= 2[6 x 2 + 2 x 2 + 2 x 6] cm2
= 2[28] cm2
= 56 cm2
Thus, the required total surface area of the cuboid = 56 cm2.