A road roller makes 250 complete revolution to move once over to

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86. A road roller makes 250 complete revolution to move once over to once level a road. Find the area of the road levelled if the diameter of the road roller is 84 cm and length is 1 m.


A road roller is a cylinder, such that
                Radius  = 84 over 2 space cm space equals space 42 space cm
            Length (h) = 1m = 100 cm
∵       Lateral surface area of a cylinder = space space 2 πrh
∴       Lateral surface area of the road roller
                                        space space space space equals space 2 cross times 22 over 7 cross times 42 cross times 100 space cm squared
                                             equals space 2 cross times 22 cross times 6 cross times 100 space cm squared
∴        Area of road levelled in 1 revolution = 26400 cm2
rightwards double arrow      Area of road levelled in 250 revolutions
                                                           equals space 250 space cross times space 26400 space cm squared

                                                           equals space fraction numerator 250 cross times 26400 over denominator 100 cross times 100 end fraction straight m squared

                                                            equals space fraction numerator 25 cross times 264 over denominator 10 end fraction space straight m squared space equals space 6600 over 10 space straight m squared

                                                             space equals space 660 space straight m squared.
 
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