Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.
Let the length of the garden be x m and width bey m.
Case I. x = y + 4
⇒ x - y = 4
Case II.
Half perimeter = 36
⇒ x + y =36
So algebraic representation be
x - y = 4
x + y = 36
Graphical representation :
We have, x - y = 4
⇒ x = 4 + y
Thus, we have following table
x + y = 36
⇒ x = 36 - y
Thus, we have following table :
Fig. 3.10.
If we plot the graph of both the equations, we find that the two lines intersect at the point (20, 16). So, x = 20, y = 16 is the required solution of the given equation i.e., the length of the garden is 20 m and breadth be 16 m.
Given the linear equations 2x + 3y - 8 = 0, write another linear equation in two variables such that the geometrical representing of the pair so formed is :
(i) intersecting lines
(ii) parallel lines
(iii) coincident lines.
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