Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.
x – 3y – 3 = 0
3x – 9y – 2 = 0
Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.
2x + y = 5
3x + 2y = 8
Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.
3x - 5y = 20
6x - 10y = 40
Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.
x - 3y - 7 = 0
3x - 3y - 15 = 0
For which values of a and b does the following pair of linear equations have an infinite number of solutions ?
2x + 3y = 7
(a - b) x + (a + b) y = 3a + b - 2
For which value of k will the following pair of linear equations have no solution?
3x + y = 1 (2k – 1) x + (k – 1) y = 2k + 1
Solve the following pair of linear equations by the substitution and cross-multiplication methods :
8x + 5y = 9
3x + 2y = 4
(i) Let the fixed hostel charges be Rs. x and the cost of food per day Rs. y (Running charges)
Case I. Hostel charges of ‘A’
Fixed charges be Rs. x and cost of food for 20 days = 20y According to Question,
x + 20y = 1000
Case II. Hostel charges of ‘B’
Fixed charges be Rs. x and cost of food for 26 days = 26y According to question,
x + 26y = 1180
Thus, we have following equations
x + 20y = 1000
x + 2 6y = 1180
or x + 20y - 1000 = 0
x + 26y- 1180 = 0
Now, by using cross multiplication method,
Hence, fixed charges is Rs. 400 and cost of food per day is Rs. 30.