Represent the following pair of equations graphically and write the coordinates of points where the lines intersect y-axis :
x + 3y = 6
2x - 3y = 12
Let the digit at 10’s place by x.
And, digit of unit’s place be y.
Then, Number = 10x + y
Case I. 10x + y = 8(x + y) + 1
⇒10x + y = 8x + 8y + 1
⇒ 10x - 8x + y - 8y = 1
⇒ 2x - 7y = 1
Case II. 10x + y = 13(x - y) + z
⇒ 10x + y = 13x - 13y + 2
⇒ 10x - 13x + y + 13y = 2
⇒ -3x + 14y = 2
Thus, we have, 2x - 7y = 1 ...(i)
-3x + 14y = 2 ...(ii)
From (i), we have 2x - 7y = 1
Subtituting the value of (ii) and (iii), we get
Putting the value of y (iii), we get
Hence, Number = 10x + y
= 10(4) + 1 =4 0 + 1 = 41