Let the speed of the train be x km/hr and that of the car be y km/hr.
We have following cases :
Case I. When he travels 250 km by train and the rest by car:
In this case, we have
Time taken by the man to travel 250 km by train
Time taken by the man to travel (370 - 250)
According to the given condition
Case II. When he travels 130 km by train and the rest by car:
Time taken by the man to travel 130 km by train
Time taken by the man to travel (370 - 130)
According to the given condition
Thus, we have following system of equations :
125u + 60 v = 2 ....(i)
130u + 240v =
Multiplying equation (iii) by 4 the above system of equations becomes
500u + 240v = 8 ...(iii)
130u + 240v =
Subtracting equation (vi) from equation (iv), we get
5 + 240v = 8
Hence, Speed of the train = 100 km/hr
Speed of the car = 80 km/hr.
Solve the following system of equations by elimination method
6(ax + by) = 3a + 2b
6(bx - ay) =3b - 2a.
A motor boat whose speed is 24 km/h in still water takes 1 hour more to go 32km upstream than to return downstream to the same spot. Find the speed of the stream.
If the points A(k + 1, 2k), B(3k, 2k + 3) and C(5k – 1, 5k) are collinear, then find the value of k.