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Mathematics : Permutations and Combinations

Short Answer Type

41. Find L.C.M. and H.C.F. of 2 x 2!, 4! and 3 x 5!

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$space space space space space space space fraction numerator left parenthesis 2 straight n right parenthesis factorial over denominator straight n factorial end fraction space equals space left square bracket 1 times 3 times 5 times........... space left parenthesis 2 straight n minus 1 right parenthesis right square bracket 2 to the power of straight n$