How many words, with or without meaning, can be formed using all

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 Multiple Choice QuestionsShort Answer Type

71. How many 3-digit numbers can be formed by using digits 1 to 9 if no digit is repeated?  
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72.

How many 4-digit numbers are there if no digit is repeated?

Or

How many numbers are there between 1000 and 9999 so that no digit is repeated?

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73. How many words with or without meaning can be formed using all the letters of the word ‘EQUATION’ using each letter exactly once?

Additional part: How many of these words begin with E and end with N?
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74. How many words with or without meaning can be formed using all the letters of the word ‘MONDAY’ assuming, that no letter is repeated, if 4 letters are used at a time.


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75. How many words with or without meaning can be formed using all the letters of the word ‘MONDAY’ assuming, that no letter is repeated, if all letters are used at a time.rightwards double arrow     


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76. How many words with or without meaning can be formed using all the letters of the word ‘MONDAY’ assuming, that no letter is repeated, if all letters are used but the first letter is a vowel?


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77. How many words, with or without meaning, can be formed with the letters of word ‘MONDAY’ assuming, that no letter is repeated, if 4 letters are used but the first letter is a vowel ?
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78.

How many words, with or without meaning, can be formed using all the letters of the word EQUATION at a time so that the vowels and consonants occur together?

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79.

How many words, with or without meaning, can be formed using all the letters of the word EQUATION at a time so that no two consonants are together.


Number of letters = (all distinct)

Number of vowels = 5 (e, i, o, u, a)

Number of consonants = 3 (q, t, n)

Arrange the vowels in a row by leaving one place between every two vowels.

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#6 {main}</pre>                   ...(i)

circled times    V    circled times    V     circled times   V   circled times    V    circled times   V     circled times
 1             2                 3           4            5            6

Number of places for the consonants, so that no two of them are together = 6

Number of consonants = 3

rightwards double arrow                           n = 6,  r = 3

Number of permutations of arranging consonants:

                           equals straight P presuperscript 6 subscript 3 space equals space fraction numerator 6 factorial over denominator 3 factorial end fraction space equals space 6 space straight x space 5 space straight x space 4 equals 120                           ...(ii)

Hence, using (i) and (ii), the number of words formed so that no two consonants are together, using fundamental principle of counting

                             = 120 x 120 = 14400




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80. In how many ways can 6-girls and 4 boys be seated in a row so that no two boys are together?
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