In how many ways can 5 girls be seated in a row so that two girls Ridhi and Sanya are:
(a) always together (b) never together
Number of girls = 5
(a) Consider Ridhi and Sanya together as one girl.
Now, number of girls becomes 4
Number of permutation of arranging these 4 girls =
But, the two girls Ridhi and Sanya can be arranged in ways or 2! ways or 2 ways.
By fundamental principle of counting, the required number of permutations = 24 x 2 = 48
(b) Total number of permutations =
Number of permutations in wich Ridhi and Sanya are never together:
= 120 - 48 = 72
(b) there is no restriction as to the number of prizes that a boy may get.
(c) no boy sets all prizes.
There are 8 students appearing for an examination, of which 3 appear in mathematics paper, and 5 in other different subjects. In how many ways can they be seated if
(a) all the students appearing for mathematics paper are together.
(b) the students appearing for mathematics paper are not all together.
(c) no two students appearing in mathematics paper are seated together ?