In how many ways can 5 girls be seated in a row so that two girls Ridhi and Sanya are:
(a) always together (b) never together
Number of digits = 6 (all different)
Number of digits used = 6
(a) Digits are not repeated n = 6, r = 6
Number of permutations =
Hence, the numbers formed = 720.
(b) The digits may be repeated.
Number of arrangements =
Hence, numbers formed = 46656.
In part (a), the numbers are to be odd.
Fix box 6 for an odd number.
Number of odd digits = 3 (5, 7, 9)
Number of boxes = 1
n = 3, r = 1
Number of permutations =
The remaining 5-digits are to be arranged in 5 boxes.
Number of permutations =
∴ Total numbers formed = 3 x 120 = 360.
(b) there is no restriction as to the number of prizes that a boy may get.
(c) no boy sets all prizes.
There are 8 students appearing for an examination, of which 3 appear in mathematics paper, and 5 in other different subjects. In how many ways can they be seated if
(a) all the students appearing for mathematics paper are together.
(b) the students appearing for mathematics paper are not all together.
(c) no two students appearing in mathematics paper are seated together ?