Short Answer TypeWrite the following in the usual form.
(i) 10 x 5 + 6 (ii) 100 x 7 + 10 x 1 + 8 (iii) 100 x a + 10 x c + b
Check what the result would have been if sundaram had chosen the numbers shown below. 1. 27 2. 39 3. 64 4. 17
1. Chosen number = 27
Number with reversed digits = 72
Sum of the two numbers = 27 + 72 = 99
Now, 99 = 11[9]
= 11[2 + 7]
= 11(Sum of the digits of the chosen number)
2. Chosen number = 39
Number with reversed digits = 93
Sum of the two numbers = 39 + 93 = 132
Now, 132 + 11 = 12
i,e, 132 = 11[12]
= 11 [ 3 + 9]
= 11 [ Sum of the digits of the chosen number]
3. Chosen number = 64
Number with reversed digits = 46
Sum = 64 + 46 = 110
Now, 110 = 11[10]
= 11[6 + 4]
= 11[ Sum of the digits of the chosen number
4. Chosen number = 17
Number with reversed digits = 71
Sum = 17 + 71 = 88
Now, 88 = 11[8]
= 11[1+7]
= 11[Sum of the digits of the chosen number]
Check what result would have been if Sundaram had chosen the numbers shown. 1.17 2.21 3.96 4.37.
Check what the result would have been if Minakshi had chosen the numbers shown below. In each case keep a record of the quotient obtained at the end.
Check what the result would have been if Sudaram had chosen the numbers shown below. 1. 417 2. 632 3. 117 4. 937
Find the values of the letters in each of the following and give reasons for the steps involved.
3 A
+ 2 5
_____
B 2
____
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