Short Answer TypeWrite the following in the usual form.
(i) 10 x 5 + 6 (ii) 100 x 7 + 10 x 1 + 8 (iii) 100 x a + 10 x c + b
Check what the result would have been if sundaram had chosen the numbers shown below. 1. 27 2. 39 3. 64 4. 17
Check what result would have been if Sundaram had chosen the numbers shown. 1.17 2.21 3.96 4.37.
Check what the result would have been if Minakshi had chosen the numbers shown below. In each case keep a record of the quotient obtained at the end.
1. 132 Chosen number = 132
Reversed number = 231
Difference = 231 - 132
= 99
We have 99 + 99 = 1, remainder = 0
2. 469 Chosen number = 469
Reversed number = 964
Difference = 964 - 469 = 495
We have 495 + 99 = 5, remainder = 0
3. Chosen number = 737
Reversed number = 737
We have dirrerence = 737 - 737 = 0
0 + 99 = 0, remainder = 0
4. Chosen number = 901
Reversed number = 109
Differende = 901 - 109
= 792
We have 792 + 99 = 8, remainder = 0
Forming three digit number with given three dgits.
Check what the result would have been if Sudaram had chosen the numbers shown below. 1. 417 2. 632 3. 117 4. 937
Find the values of the letters in each of the following and give reasons for the steps involved.
3 A
+ 2 5
_____
B 2
____
One Word Answers
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