If the division N ÷ 2 leaves no remainder (i.e, zero remainder), what might be the one’s digit of N?
Suppose that the division N ÷ 5 leaves a remainder of 4 and the division N ÷ 2 leaves a remainder of 1. What must be the one’s digit of N?
Check the divisibility of the following number by 9.
1. 108 2. 616 3. 294
4. 432 5. 927
1. 108
∵ 1 + 0 + 8 = 9
and 9 is divisible by 9 (∵ 9 9=1 and remainder = 0)
∴ 108 is divisible by 9.
2. 616
We have 6 + 1 + 6 = 13
and 13 9 = 1, remainder = 4
i.e. 13 is not divisible by 9.
∴ 616 is also not divisible by 9.
3. 294
We have 2 + 9 + 4 = 15
and 15 9 = 1, remainder = 6
i.e. 15 is not divisible by 9.
∴ 294 is not divisible by 9.
4. 432
We have 4 + 3 +2 = 9
and 9 9 = 1, remainder =0
∴ 432 is divisble by 9.
5. 927
We have 9 + 2 + 7 = 18
and 18 9 = 2, remainder = 0
i.e. 18 is divisible by 9.
∴ 927 is not also divisible by 9.