Trying to find the right answer to this..

We know that a quadratic polynomial when the sum and product of its zeroes are given by p(x) = K {x 2 – (sum of the zeroes) x + Product of zeroes}, where K is a constant. Therefore, required quadratic polynomial p(x) is given by p(x) K[x 2 –(1x)+(–2)] = K (x 2 – x– 2).

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Polynomials

Short Answer Type

361. Prove that x² + 6x + 15 has no zero.

1592 Views

362. How many zeroes can, a polynomial of degree n have ?

136 Views

363.

The graph of the polynomial y = ax² + bx + c is shown in Fig. 2.2. Write the value of b² – 4ac.

y = ax²+ bx + c.

115 Views

364. Write the polynomial, the product and soon of whose heroes are

negative 9 over 2 space and space minus 3 over 2

respectively.

137 Views

365. What is the product of the zeroes of quadratic polynomial 3x² + 11x – 6 ?

125 Views

366. Find the number of zeroes of the function, whose graph is given below in Fig.

497 Views

367. Find a quadratic polynomial, the sum and product of whose zeroes are 1 and –2 respectively.

We know that a quadratic polynomial when the sum and product of its zeroes are given by
p(x) = K {x² – (sum of the zeroes) x + Product of zeroes},
where K is a constant.
Therefore, required quadratic polynomial p(x) is given by
p(x) K[x²–(1x)+(–2)] = K (x² – x– 2).

856 Views