If α, β are the zeroes of the polynomial p(x) = 4x2 + 3x + 7

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372. If α, β are the zeroes of the polynomial p(x) = 4x2 + 3x + 7. Find the value of space space 1 over straight alpha plus 1 over straight beta.


We have,
p(x) = 4x2 + 3x + 7, then
Sum of the zeroes (α + β)
equals fraction numerator negative Coeff. of space straight x over denominator Coeff. space of space straight x squared end fraction equals fraction numerator negative 3 over denominator 4 end fraction
And, product of the zeroes (α. β)
                                equals space fraction numerator Constant space term over denominator Coeff. of space straight x squared end fraction equals 7 over 4

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                              equals fraction numerator negative begin display style 3 over 4 end style over denominator begin display style 7 over 4 end style end fraction equals negative 3 over 7. Ans.  
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