4x2 – 4x – 3
= 4x2 – 6x + 2x – 3
= 2x (2x – 3) + 1 (2x – 3)
= (2x – 3) (2x + 1)
So, 4x2 – 4x – 3 = 0 ⇒ (2x – 3) (2x + 1) = 0
⇒ 2x – 3 = 0 or 2x + 1 = 0
⇒ x = 3/2 or x = – 1/2
∴ Zeroes of are
Now,
Sum of zeroes =
=
and product of zeroes =
If α and β are the zeroes of the quadratic polynomial ax2 + bx + c. Find the value of α2– β2.