p(x) = (x - 1)(x + 1)∴ p(0) = (0 - 1)(0 + 1) = (- 1)(1) = - 1,p(1) = (1 - 1)(1 + 1) = (0)(2) = 0,and, p(2) = (2 - 1)(2 + 1) = (1)(3) = 3