Trying to find the right answer to this..

p(x) = x 2 - 1, x = 1, - 1 p(1) = (1) 2 - 1 = 1 - 1 = 0 p(-1) = (-1) 2 - 1 = 1 - 1 = 0 ∴ 1, - 1 are zeroes of p(x).

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p(x) = x² - 1, x = 1, - 1
p(1) = (1)² - 1 = 1 - 1 = 0
p(-1) = (-1)² - 1 = 1 - 1 = 0
∴ 1, - 1 are zeroes of p(x).

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